57625 / Kakatiya Fast Passenger
काकतिया फास्ट पैसेंजर
Today Departure from Secunderabad Junction is cancelled
The following table shows the schedule of 57625/Kakatiya Fast Passenger including timing along with its arrival and departure time at each station with Platform number. The distance column shows the distance traveled by the train from its starting point from Secunderabad Junction
.Departs @ 18:40 (Secunderabad Junction)
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Arrives @ 04:15 +1 night (Manuguru)
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Kakatiya Fast Passenger (57625) Schedule
S#
Code
Station
Arr.
Dept.
Halt
PF
Dist.
Day
Zone
The train, during its journey from Secunderabad Junction, crosses 35 railway station and terminates at Manuguru. It takes 9 hours and 35 minutes for this train to complete its entire journey of 330 kilometers.
The return train is 57626.